Base | Representation |
---|---|
bin | 1011111011010101110111… |
… | …1001001011010101010011 |
3 | 1201102200210220101200220102 |
4 | 2332311131321023111103 |
5 | 3204330144232040103 |
6 | 43520312243003015 |
7 | 2522314611245432 |
oct | 276653571132523 |
9 | 51380726350812 |
10 | 13114110424403 |
11 | 41a67324a556a |
12 | 157972906946b |
13 | 74186992a2c1 |
14 | 334a250a5119 |
15 | 17b1dc567e88 |
hex | bed5de4b553 |
13114110424403 has 8 divisors (see below), whose sum is σ = 14092775382672. Its totient is φ = 12158472877056.
The previous prime is 13114110424361. The next prime is 13114110424409. The reversal of 13114110424403 is 30442401141131.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13114110424403 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13114110424409) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5756851550 + ... + 5756853827.
It is an arithmetic number, because the mean of its divisors is an integer number (1761596922834).
Almost surely, 213114110424403 is an apocalyptic number.
13114110424403 is a deficient number, since it is larger than the sum of its proper divisors (978664958269).
13114110424403 is a wasteful number, since it uses less digits than its factorization.
13114110424403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11513705461.
The product of its (nonzero) digits is 4608, while the sum is 29.
Adding to 13114110424403 its reverse (30442401141131), we get a palindrome (43556511565534).
The spelling of 13114110424403 in words is "thirteen trillion, one hundred fourteen billion, one hundred ten million, four hundred twenty-four thousand, four hundred three".
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