1311411112041 has 8 divisors (see below), whose sum is σ = 1808842913280. Its totient is φ = 844126692752.

The previous prime is 1311411112031. The next prime is 1311411112049. The reversal of 1311411112041 is 1402111141131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1311411112041 - 2¹⁵ = 1311411079273 is a prime.

It is a super-2 number, since 2×1311411112041² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1311411111999 and 1311411112017.

It is not an unprimeable number, because it can be changed into a prime (1311411112049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7536845385 + ... + 7536845558.

It is an arithmetic number, because the mean of its divisors is an integer number (226105364160).

Almost surely, 2^{1311411112041} is an apocalyptic number.

It is an amenable number.

1311411112041 is a deficient number, since it is larger than the sum of its proper divisors (497431801239).

1311411112041 is a wasteful number, since it uses less digits than its factorization.

1311411112041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15073690975.

The product of its (nonzero) digits is 96, while the sum is 21.

Adding to 1311411112041 its reverse (1402111141131), we get a palindrome (2713522253172).

The spelling of 1311411112041 in words is "one trillion, three hundred eleven billion, four hundred eleven million, one hundred twelve thousand, forty-one".