1311411616303 has 4 divisors (see below), whose sum is σ = 1368429512688. Its totient is φ = 1254393719920.

The previous prime is 1311411616301. The next prime is 1311411616343. The reversal of 1311411616303 is 3036161141131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1311411616303 - 2¹ = 1311411616301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311411616301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28508948158 + ... + 28508948203.

It is an arithmetic number, because the mean of its divisors is an integer number (342107378172).

Almost surely, 2^{1311411616303} is an apocalyptic number.

1311411616303 is a deficient number, since it is larger than the sum of its proper divisors (57017896385).

1311411616303 is an equidigital number, since it uses as much as digits as its factorization.

1311411616303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 57017896384.

The product of its (nonzero) digits is 3888, while the sum is 31.

Adding to 1311411616303 its reverse (3036161141131), we get a palindrome (4347572757434).

The spelling of 1311411616303 in words is "one trillion, three hundred eleven billion, four hundred eleven million, six hundred sixteen thousand, three hundred three".