13114122023113 has 4 divisors (see below), whose sum is σ = 13114134266128. Its totient is φ = 13114109780100.

The previous prime is 13114122023099. The next prime is 13114122023137. The reversal of 13114122023113 is 31132022141131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13114122023113 - 2⁵ = 13114122023081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13114122023413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4342431 + ... + 6714532.

It is an arithmetic number, because the mean of its divisors is an integer number (3278533566532).

Almost surely, 2^{13114122023113} is an apocalyptic number.

It is an amenable number.

13114122023113 is a deficient number, since it is larger than the sum of its proper divisors (12243015).

13114122023113 is a wasteful number, since it uses less digits than its factorization.

13114122023113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12243014.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 13114122023113 its reverse (31132022141131), we get a palindrome (44246144164244).

The spelling of 13114122023113 in words is "thirteen trillion, one hundred fourteen billion, one hundred twenty-two million, twenty-three thousand, one hundred thirteen".