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1311413200023 = 3437137733341
BaseRepresentation
bin10011000101010110010…
…100010110010010010111
311122100222122022002100010
4103011112110112102113
5132441233234400043
62442242132051303
7163514020164123
oct23052624262227
94570878262303
101311413200023
11466192621303
121921b1763b33
1396886805634
1447689298583
15241a5dd4133
hex13156516497

1311413200023 has 4 divisors (see below), whose sum is σ = 1748550933368. Its totient is φ = 874275466680.

The previous prime is 1311413200001. The next prime is 1311413200033. The reversal of 1311413200023 is 3200023141131.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1311413200023 - 29 = 1311413199511 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311413200033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218568866668 + ... + 218568866673.

It is an arithmetic number, because the mean of its divisors is an integer number (437137733342).

Almost surely, 21311413200023 is an apocalyptic number.

1311413200023 is a deficient number, since it is larger than the sum of its proper divisors (437137733345).

1311413200023 is an equidigital number, since it uses as much as digits as its factorization.

1311413200023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 437137733344.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 1311413200023 its reverse (3200023141131), we get a palindrome (4511436341154).

The spelling of 1311413200023 in words is "one trillion, three hundred eleven billion, four hundred thirteen million, two hundred thousand, twenty-three".

Divisors: 1 3 437137733341 1311413200023