Base | Representation |
---|---|
bin | 11101110100010110111001… |
… | …000010111101100001100011 |
3 | 122012022222201112110221220210 |
4 | 131310112321002331201203 |
5 | 114142104431244310034 |
6 | 1142525300024505203 |
7 | 36423435453213144 |
oct | 3564267102754143 |
9 | 565288645427823 |
10 | 131141341010019 |
11 | 388708041749aa |
12 | 128600a191b203 |
13 | 58237631a9162 |
14 | 24553bbd8bacb |
15 | 10264496228e9 |
hex | 7745b90bd863 |
131141341010019 has 4 divisors (see below), whose sum is σ = 174855121346696. Its totient is φ = 87427560673344.
The previous prime is 131141341009981. The next prime is 131141341010021. The reversal of 131141341010019 is 910010143141131.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 131141341010019 - 231 = 131139193526371 is a prime.
It is a super-2 number, since 2×1311413410100192 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131141341010039) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21856890168334 + ... + 21856890168339.
It is an arithmetic number, because the mean of its divisors is an integer number (43713780336674).
Almost surely, 2131141341010019 is an apocalyptic number.
131141341010019 is a deficient number, since it is larger than the sum of its proper divisors (43713780336677).
131141341010019 is an equidigital number, since it uses as much as digits as its factorization.
131141341010019 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 43713780336676.
The product of its (nonzero) digits is 1296, while the sum is 30.
The spelling of 131141341010019 in words is "one hundred thirty-one trillion, one hundred forty-one billion, three hundred forty-one million, ten thousand, nineteen".
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