131141342031333 has 4 divisors (see below), whose sum is σ = 174855122708448. Its totient is φ = 87427561354220.

The previous prime is 131141342031331. The next prime is 131141342031373. The reversal of 131141342031333 is 333130243141131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131141342031333 - 2¹ = 131141342031331 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131141342031294 and 131141342031303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131141342031331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21856890338553 + ... + 21856890338558.

It is an arithmetic number, because the mean of its divisors is an integer number (43713780677112).

Almost surely, 2^{131141342031333} is an apocalyptic number.

It is an amenable number.

131141342031333 is a deficient number, since it is larger than the sum of its proper divisors (43713780677115).

131141342031333 is an equidigital number, since it uses as much as digits as its factorization.

131141342031333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43713780677114.

The product of its (nonzero) digits is 23328, while the sum is 33.

Adding to 131141342031333 its reverse (333130243141131), we get a palindrome (464271585172464).

The spelling of 131141342031333 in words is "one hundred thirty-one trillion, one hundred forty-one billion, three hundred forty-two million, thirty-one thousand, three hundred thirty-three".