Base | Representation |
---|---|
bin | 1011111011010101111101… |
… | …0100101110101011110011 |
3 | 1201102200212120120000120202 |
4 | 2332311133110232223303 |
5 | 3204330221403034212 |
6 | 43520314501225415 |
7 | 2522315322244130 |
oct | 276653724565363 |
9 | 51380776500522 |
10 | 13114134424307 |
11 | 41a6744aa7aa4 |
12 | 157973510226b |
13 | 7418718b1227 |
14 | 334a28351587 |
15 | 17b1de7090c2 |
hex | bed5f52eaf3 |
13114134424307 has 4 divisors (see below), whose sum is σ = 14987582199216. Its totient is φ = 11240686649400.
The previous prime is 13114134424291. The next prime is 13114134424361. The reversal of 13114134424307 is 70342443141131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13114134424307 - 24 = 13114134424291 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13114134424387) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 936723887444 + ... + 936723887457.
It is an arithmetic number, because the mean of its divisors is an integer number (3746895549804).
Almost surely, 213114134424307 is an apocalyptic number.
13114134424307 is a deficient number, since it is larger than the sum of its proper divisors (1873447774909).
13114134424307 is an equidigital number, since it uses as much as digits as its factorization.
13114134424307 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1873447774908.
The product of its (nonzero) digits is 96768, while the sum is 38.
Adding to 13114134424307 its reverse (70342443141131), we get a palindrome (83456577565438).
The spelling of 13114134424307 in words is "thirteen trillion, one hundred fourteen billion, one hundred thirty-four million, four hundred twenty-four thousand, three hundred seven".
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