13114134424345 has 4 divisors (see below), whose sum is σ = 15736961309220. Its totient is φ = 10491307539472.

The previous prime is 13114134424291. The next prime is 13114134424361. The reversal of 13114134424345 is 54342443141131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 5879174939401 + 7234959484944 = 2424701^2 + 2689788^2 .

It is a cyclic number.

It is not a de Polignac number, because 13114134424345 - 2¹³ = 13114134416153 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13114134424298 and 13114134424307.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1311413442430 + ... + 1311413442439.

It is an arithmetic number, because the mean of its divisors is an integer number (3934240327305).

Almost surely, 2^{13114134424345} is an apocalyptic number.

It is an amenable number.

13114134424345 is a deficient number, since it is larger than the sum of its proper divisors (2622826884875).

13114134424345 is an equidigital number, since it uses as much as digits as its factorization.

13114134424345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2622826884874.

The product of its digits is 276480, while the sum is 40.

Adding to 13114134424345 its reverse (54342443141131), we get a palindrome (67456577565476).

The spelling of 13114134424345 in words is "thirteen trillion, one hundred fourteen billion, one hundred thirty-four million, four hundred twenty-four thousand, three hundred forty-five".