Base | Representation |
---|---|
bin | 11000011011010101… |
… | …00010100111101011 |
3 | 1020211221121020011210 |
4 | 30031222202213223 |
5 | 203324211020142 |
6 | 10005145524203 |
7 | 642660333321 |
oct | 141552424753 |
9 | 36757536153 |
10 | 13114157547 |
11 | 561a666737 |
12 | 265baa3663 |
13 | 130cc3154a |
14 | 8c59a3d11 |
15 | 51b4a149c |
hex | 30daa29eb |
13114157547 has 4 divisors (see below), whose sum is σ = 17485543400. Its totient is φ = 8742771696.
The previous prime is 13114157543. The next prime is 13114157591. The reversal of 13114157547 is 74575141131.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 74575141131 = 3 ⋅24858380377.
It is not a de Polignac number, because 13114157547 - 22 = 13114157543 is a prime.
It is a super-2 number, since 2×131141575472 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13114157543) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2185692922 + ... + 2185692927.
It is an arithmetic number, because the mean of its divisors is an integer number (4371385850).
Almost surely, 213114157547 is an apocalyptic number.
13114157547 is a deficient number, since it is larger than the sum of its proper divisors (4371385853).
13114157547 is an equidigital number, since it uses as much as digits as its factorization.
13114157547 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4371385852.
The product of its digits is 58800, while the sum is 39.
Adding to 13114157547 its reverse (74575141131), we get a palindrome (87689298678).
The spelling of 13114157547 in words is "thirteen billion, one hundred fourteen million, one hundred fifty-seven thousand, five hundred forty-seven".
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