Base | Representation |
---|---|
bin | 11101110100010111100110… |
… | …011110111010000001000010 |
3 | 122012100001200122212211110022 |
4 | 131310113212132322001002 |
5 | 114142113011421413102 |
6 | 1142525503415333442 |
7 | 36423463400522222 |
oct | 3564274636720102 |
9 | 565301618784408 |
10 | 131142103310402 |
11 | 388710654a6518 |
12 | 12860275081282 |
13 | 58238550bc582 |
14 | 2455451302082 |
15 | 10264914ee5a2 |
hex | 7745e67ba042 |
131142103310402 has 4 divisors (see below), whose sum is σ = 196713154965606. Its totient is φ = 65571051655200.
The previous prime is 131142103310237. The next prime is 131142103310423. The reversal of 131142103310402 is 204013301241131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 120275725086841 + 10866378223561 = 10967029^2 + 3296419^2 .
It is a super-2 number, since 2×1311421033104022 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32785525827599 + ... + 32785525827602.
Almost surely, 2131142103310402 is an apocalyptic number.
131142103310402 is a deficient number, since it is larger than the sum of its proper divisors (65571051655204).
131142103310402 is an equidigital number, since it uses as much as digits as its factorization.
131142103310402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65571051655203.
The product of its (nonzero) digits is 1728, while the sum is 26.
Adding to 131142103310402 its reverse (204013301241131), we get a palindrome (335155404551533).
The spelling of 131142103310402 in words is "one hundred thirty-one trillion, one hundred forty-two billion, one hundred three million, three hundred ten thousand, four hundred two".
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