Base | Representation |
---|---|
bin | 11101110100010111100110… |
… | …100010000010110110101010 |
3 | 122012100001200201102121220011 |
4 | 131310113212202002312222 |
5 | 114142113012124224114 |
6 | 1142525503445122134 |
7 | 36423463410516451 |
oct | 3564274642026652 |
9 | 565301621377804 |
10 | 131142104133034 |
11 | 38871065a08585 |
12 | 128602753b934a |
13 | 5823855319b37 |
14 | 2455451477b98 |
15 | 10264916131c4 |
hex | 7745e6882daa |
131142104133034 has 4 divisors (see below), whose sum is σ = 196713156199554. Its totient is φ = 65571052066516.
The previous prime is 131142104133031. The next prime is 131142104133043. The reversal of 131142104133034 is 430331401241131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 99054943443225 + 32087160689809 = 9952635^2 + 5664553^2 .
It is a junction number, because it is equal to n+sod(n) for n = 131142104132987 and 131142104133005.
It is not an unprimeable number, because it can be changed into a prime (131142104133031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32785526033257 + ... + 32785526033260.
Almost surely, 2131142104133034 is an apocalyptic number.
131142104133034 is a deficient number, since it is larger than the sum of its proper divisors (65571052066520).
131142104133034 is an equidigital number, since it uses as much as digits as its factorization.
131142104133034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65571052066519.
The product of its (nonzero) digits is 10368, while the sum is 31.
Adding to 131142104133034 its reverse (430331401241131), we get a palindrome (561473505374165).
The spelling of 131142104133034 in words is "one hundred thirty-one trillion, one hundred forty-two billion, one hundred four million, one hundred thirty-three thousand, thirty-four".
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