131142120010441 has 4 divisors (see below), whose sum is σ = 131142902597584. Its totient is φ = 131141337423300.

The previous prime is 131142120010409. The next prime is 131142120010459. The reversal of 131142120010441 is 144010021241131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131142120010441 - 2⁵ = 131142120010409 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131142120010471) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 391042155 + ... + 391377376.

It is an arithmetic number, because the mean of its divisors is an integer number (32785725649396).

Almost surely, 2^{131142120010441} is an apocalyptic number.

It is an amenable number.

131142120010441 is a deficient number, since it is larger than the sum of its proper divisors (782587143).

131142120010441 is an equidigital number, since it uses as much as digits as its factorization.

131142120010441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 782587142.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 131142120010441 its reverse (144010021241131), we get a palindrome (275152141251572).

The spelling of 131142120010441 in words is "one hundred thirty-one trillion, one hundred forty-two billion, one hundred twenty million, ten thousand, four hundred forty-one".