13114220333 has 4 divisors (see below), whose sum is σ = 13176373248. Its totient is φ = 13052067420.

The previous prime is 13114220303. The next prime is 13114220369. The reversal of 13114220333 is 33302241131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13114220333 - 2¹⁶ = 13114154797 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13114220299 and 13114220308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13114220303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31076141 + ... + 31076562.

It is an arithmetic number, because the mean of its divisors is an integer number (3294093312).

Almost surely, 2^13114220333 is an apocalyptic number.

It is an amenable number.

13114220333 is a deficient number, since it is larger than the sum of its proper divisors (62152915).

13114220333 is an equidigital number, since it uses as much as digits as its factorization.

13114220333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 62152914.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 13114220333 its reverse (33302241131), we get a palindrome (46416461464).

The spelling of 13114220333 in words is "thirteen billion, one hundred fourteen million, two hundred twenty thousand, three hundred thirty-three".