131142204110113 has 4 divisors (see below), whose sum is σ = 149876804697280. Its totient is φ = 112407603522948.

The previous prime is 131142204110083. The next prime is 131142204110123. The reversal of 131142204110113 is 311011402241131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131142204110113 - 2²⁵ = 131142170555681 is a prime.

It is a super-3 number, since 3×131142204110113³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131142204110123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9367300293573 + ... + 9367300293586.

It is an arithmetic number, because the mean of its divisors is an integer number (37469201174320).

Almost surely, 2^{131142204110113} is an apocalyptic number.

It is an amenable number.

131142204110113 is a deficient number, since it is larger than the sum of its proper divisors (18734600587167).

131142204110113 is an equidigital number, since it uses as much as digits as its factorization.

131142204110113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18734600587166.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 131142204110113 its reverse (311011402241131), we get a palindrome (442153606351244).

The spelling of 131142204110113 in words is "one hundred thirty-one trillion, one hundred forty-two billion, two hundred four million, one hundred ten thousand, one hundred thirteen".