Base | Representation |
---|---|
bin | 111101000100010101… |
… | …1111100101101101011 |
3 | 110112111112021002212220 |
4 | 1322020223330231223 |
5 | 4122034403204011 |
6 | 140125041205123 |
7 | 12321553441266 |
oct | 1721053745553 |
9 | 415445232786 |
10 | 131142241131 |
11 | 50687415870 |
12 | 214bb3307a3 |
13 | c49c725165 |
14 | 64c1081cdd |
15 | 3628290506 |
hex | 1e88afcb6b |
131142241131 has 16 divisors (see below), whose sum is σ = 192640992768. Its totient is φ = 78693212000.
The previous prime is 131142241129. The next prime is 131142241141.
131142241131 is nontrivially palindromic in base 10.
It is a cyclic number.
It is not a de Polignac number, because 131142241131 - 21 = 131142241129 is a prime.
It is a super-2 number, since 2×1311422411312 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (131142241141) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 19669971 + ... + 19676636.
It is an arithmetic number, because the mean of its divisors is an integer number (12040062048).
Almost surely, 2131142241131 is an apocalyptic number.
131142241131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
131142241131 is a deficient number, since it is larger than the sum of its proper divisors (61498751637).
131142241131 is a wasteful number, since it uses less digits than its factorization.
131142241131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39346722.
The product of its digits is 576, while the sum is 24.
It can be divided in two parts, 131142 and 241131, that added together give a palindrome (372273).
The spelling of 131142241131 in words is "one hundred thirty-one billion, one hundred forty-two million, two hundred forty-one thousand, one hundred thirty-one".
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