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1311423356411 = 7187346193773
BaseRepresentation
bin10011000101010110111…
…011000101110111111011
311122101000100102002021122
4103011112323011313323
5132441243334401121
62442243133455455
7163514202414440
oct23052673056773
94571010362248
101311423356411
11466198328a13
121921b504158b
139688895042c
144768a77d9c7
15241a6c3d5ab
hex13156ec5dfb

1311423356411 has 4 divisors (see below), whose sum is σ = 1498769550192. Its totient is φ = 1124077162632.

The previous prime is 1311423356401. The next prime is 1311423356431. The reversal of 1311423356411 is 1146533241131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1311423356411 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1311423356401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 93673096880 + ... + 93673096893.

It is an arithmetic number, because the mean of its divisors is an integer number (374692387548).

Almost surely, 21311423356411 is an apocalyptic number.

1311423356411 is a deficient number, since it is larger than the sum of its proper divisors (187346193781).

1311423356411 is an equidigital number, since it uses as much as digits as its factorization.

1311423356411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 187346193780.

The product of its digits is 25920, while the sum is 35.

Adding to 1311423356411 its reverse (1146533241131), we get a palindrome (2457956597542).

The spelling of 1311423356411 in words is "one trillion, three hundred eleven billion, four hundred twenty-three million, three hundred fifty-six thousand, four hundred eleven".

Divisors: 1 7 187346193773 1311423356411