Base | Representation |
---|---|
bin | 11101110100010111111000… |
… | …110100110011010111001010 |
3 | 122012100002111002221010101022 |
4 | 131310113320310303113022 |
5 | 114142114124211241302 |
6 | 1142525554131152442 |
7 | 36423504125264522 |
oct | 3564277064632712 |
9 | 565302432833338 |
10 | 131142411040202 |
11 | 3887120317a471 |
12 | 12860340145722 |
13 | 58238a3a95803 |
14 | 2455480128682 |
15 | 10264ad5388a2 |
hex | 7745f8d335ca |
131142411040202 has 4 divisors (see below), whose sum is σ = 196713616560306. Its totient is φ = 65571205520100.
The previous prime is 131142411040181. The next prime is 131142411040231. The reversal of 131142411040202 is 202040114241131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 94214414500921 + 36927996539281 = 9706411^2 + 6076841^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32785602760049 + ... + 32785602760052.
Almost surely, 2131142411040202 is an apocalyptic number.
131142411040202 is a deficient number, since it is larger than the sum of its proper divisors (65571205520104).
131142411040202 is an equidigital number, since it uses as much as digits as its factorization.
131142411040202 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65571205520103.
The product of its (nonzero) digits is 1536, while the sum is 26.
Adding to 131142411040202 its reverse (202040114241131), we get a palindrome (333182525281333).
The spelling of 131142411040202 in words is "one hundred thirty-one trillion, one hundred forty-two billion, four hundred eleven million, forty thousand, two hundred two".
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