Base | Representation |
---|---|
bin | 11101110100010111111001… |
… | …100010111011000011100111 |
3 | 122012100002111221200100221022 |
4 | 131310113321202323003213 |
5 | 114142114140310132333 |
6 | 1142525555242241355 |
7 | 36423504333120662 |
oct | 3564277142730347 |
9 | 565302457610838 |
10 | 131142423130343 |
11 | 38871209a87a19 |
12 | 128603441b625b |
13 | 58238a6439841 |
14 | 24554819946d9 |
15 | 10264ae625c98 |
hex | 7745f98bb0e7 |
131142423130343 has 4 divisors (see below), whose sum is σ = 131153162838168. Its totient is φ = 131131683422520.
The previous prime is 131142423130333. The next prime is 131142423130351. The reversal of 131142423130343 is 343031324241131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131142423130343 - 28 = 131142423130087 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131142423130333) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5369835596 + ... + 5369860017.
It is an arithmetic number, because the mean of its divisors is an integer number (32788290709542).
Almost surely, 2131142423130343 is an apocalyptic number.
131142423130343 is a deficient number, since it is larger than the sum of its proper divisors (10739707825).
131142423130343 is a wasteful number, since it uses less digits than its factorization.
131142423130343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10739707824.
The product of its (nonzero) digits is 62208, while the sum is 35.
Adding to 131142423130343 its reverse (343031324241131), we get a palindrome (474173747371474).
The spelling of 131142423130343 in words is "one hundred thirty-one trillion, one hundred forty-two billion, four hundred twenty-three million, one hundred thirty thousand, three hundred forty-three".
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