Base | Representation |
---|---|
bin | 11101110100011000100111… |
… | …111111110000010010010111 |
3 | 122012100011112021002102021122 |
4 | 131310120213333300102113 |
5 | 114142122234311042333 |
6 | 1142530204441434155 |
7 | 36423532545132542 |
oct | 3564304777602227 |
9 | 565304467072248 |
10 | 131143202440343 |
11 | 38871579977075 |
12 | 1286052119b95b |
13 | 582399ba27212 |
14 | 2455517295859 |
15 | 1026507c62798 |
hex | 774627ff0497 |
131143202440343 has 8 divisors (see below), whose sum is σ = 131509463168160. Its totient is φ = 130777295762080.
The previous prime is 131143202440339. The next prime is 131143202440421. The reversal of 131143202440343 is 343044202341131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 131143202440343 - 22 = 131143202440339 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131143202446343) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 87770528 + ... + 89252181.
It is an arithmetic number, because the mean of its divisors is an integer number (16438682896020).
Almost surely, 2131143202440343 is an apocalyptic number.
131143202440343 is a deficient number, since it is larger than the sum of its proper divisors (366260727817).
131143202440343 is a wasteful number, since it uses less digits than its factorization.
131143202440343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 177024777.
The product of its (nonzero) digits is 82944, while the sum is 35.
Adding to 131143202440343 its reverse (343044202341131), we get a palindrome (474187404781474).
The spelling of 131143202440343 in words is "one hundred thirty-one trillion, one hundred forty-three billion, two hundred two million, four hundred forty thousand, three hundred forty-three".
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