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1311432522445 = 5262286504489
BaseRepresentation
bin10011000101010111011…
…110000011101011001101
311122101000222122202201101
4103011113132003223031
5132441303211204240
62442244102143101
7163514343341533
oct23052736035315
94571028582641
101311432522445
114661a2519551
121921b8121a91
139688a80c516
144768ba88153
15241a794e39a
hex13157783acd

1311432522445 has 4 divisors (see below), whose sum is σ = 1573719026940. Its totient is φ = 1049146017952.

The previous prime is 1311432522437. The next prime is 1311432522559. The reversal of 1311432522445 is 5442252341131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 151499214441 + 1159933308004 = 389229^2 + 1077002^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311432522445 - 23 = 1311432522437 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 131143252240 + ... + 131143252249.

It is an arithmetic number, because the mean of its divisors is an integer number (393429756735).

Almost surely, 21311432522445 is an apocalyptic number.

It is an amenable number.

1311432522445 is a deficient number, since it is larger than the sum of its proper divisors (262286504495).

1311432522445 is an equidigital number, since it uses as much as digits as its factorization.

1311432522445 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 262286504494.

The product of its digits is 115200, while the sum is 37.

Adding to 1311432522445 its reverse (5442252341131), we get a palindrome (6753684863576).

The spelling of 1311432522445 in words is "one trillion, three hundred eleven billion, four hundred thirty-two million, five hundred twenty-two thousand, four hundred forty-five".

Divisors: 1 5 262286504489 1311432522445