1311435050403 has 16 divisors (see below), whose sum is σ = 1851486215040. Its totient is φ = 822839654016.

The previous prime is 1311435050347. The next prime is 1311435050407. The reversal of 1311435050403 is 3040505341131.

It is not a de Polignac number, because 1311435050403 - 2¹⁷ = 1311434919331 is a prime.

It is a super-3 number, since 3×1311435050403³ (a number of 37 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (1311435050407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1755508 + ... + 2388446.

It is an arithmetic number, because the mean of its divisors is an integer number (115717888440).

Almost surely, 2^{1311435050403} is an apocalyptic number.

1311435050403 is a deficient number, since it is larger than the sum of its proper divisors (540051164637).

1311435050403 is a wasteful number, since it uses less digits than its factorization.

1311435050403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 673586.

The product of its (nonzero) digits is 10800, while the sum is 30.

The spelling of 1311435050403 in words is "one trillion, three hundred eleven billion, four hundred thirty-five million, fifty thousand, four hundred three".