131144013213001 has 4 divisors (see below), whose sum is σ = 131144096804992. Its totient is φ = 131143929621012.

The previous prime is 131144013212951. The next prime is 131144013213013. The reversal of 131144013213001 is 100312310441131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131144013213001 - 2⁹ = 131144013212489 is a prime.

It is a super-2 number, since 2×131144013213001² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131144013213041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39396801 + ... + 42595726.

It is an arithmetic number, because the mean of its divisors is an integer number (32786024201248).

Almost surely, 2^{131144013213001} is an apocalyptic number.

It is an amenable number.

131144013213001 is a deficient number, since it is larger than the sum of its proper divisors (83591991).

131144013213001 is an equidigital number, since it uses as much as digits as its factorization.

131144013213001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 83591990.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 131144013213001 its reverse (100312310441131), we get a palindrome (231456323654132).

The spelling of 131144013213001 in words is "one hundred thirty-one trillion, one hundred forty-four billion, thirteen million, two hundred thirteen thousand, one".