13114434001113 has 16 divisors (see below), whose sum is σ = 19459006987840. Its totient is φ = 8729358856992.

The previous prime is 13114434001093. The next prime is 13114434001117. The reversal of 13114434001113 is 31110043441131.

13114434001113 is a `hidden beast` number, since 1 + 3 + 1 + 144 + 3 + 400 + 1 + 113 = 666.

It is not a de Polignac number, because 13114434001113 - 2¹³ = 13114433992921 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13114434001117) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 377680756 + ... + 377715477.

It is an arithmetic number, because the mean of its divisors is an integer number (1216187936740).

Almost surely, 2^{13114434001113} is an apocalyptic number.

It is an amenable number.

13114434001113 is a deficient number, since it is larger than the sum of its proper divisors (6344572986727).

13114434001113 is an equidigital number, since it uses as much as digits as its factorization.

13114434001113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 755396885 (or 755396879 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 27.

Adding to 13114434001113 its reverse (31110043441131), we get a palindrome (44224477442244).

The spelling of 13114434001113 in words is "thirteen trillion, one hundred fourteen billion, four hundred thirty-four million, one thousand, one hundred thirteen".