13114434001117 has 2 divisors, whose sum is σ = 13114434001118. Its totient is φ = 13114434001116.

The previous prime is 13114434001093. The next prime is 13114434001121. The reversal of 13114434001117 is 71110043441131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9176864483556 + 3937569517561 = 3029334^2 + 1984331^2 .

It is a cyclic number.

It is not a de Polignac number, because 13114434001117 - 2⁷ = 13114434000989 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13114434001147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557217000558 + 6557217000559.

It is an arithmetic number, because the mean of its divisors is an integer number (6557217000559).

Almost surely, 2^{13114434001117} is an apocalyptic number.

It is an amenable number.

13114434001117 is a deficient number, since it is larger than the sum of its proper divisors (1).

13114434001117 is an equidigital number, since it uses as much as digits as its factorization.

13114434001117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4032, while the sum is 31.

Adding to 13114434001117 its reverse (71110043441131), we get a palindrome (84224477442248).

The spelling of 13114434001117 in words is "thirteen trillion, one hundred fourteen billion, four hundred thirty-four million, one thousand, one hundred seventeen".