13114441321001 has 4 divisors (see below), whose sum is σ = 13115767763712. Its totient is φ = 13113114878292.

The previous prime is 13114441320997. The next prime is 13114441321031. The reversal of 13114441321001 is 10012314441131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13114441321001 - 2² = 13114441320997 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13114441321031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 663206525 + ... + 663226298.

It is an arithmetic number, because the mean of its divisors is an integer number (3278941940928).

Almost surely, 2^{13114441321001} is an apocalyptic number.

It is an amenable number.

13114441321001 is a deficient number, since it is larger than the sum of its proper divisors (1326442711).

13114441321001 is an equidigital number, since it uses as much as digits as its factorization.

13114441321001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1326442710.

The product of its (nonzero) digits is 1152, while the sum is 26.

Adding to 13114441321001 its reverse (10012314441131), we get a palindrome (23126755762132).

The spelling of 13114441321001 in words is "thirteen trillion, one hundred fourteen billion, four hundred forty-one million, three hundred twenty-one thousand, one".