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13114441320997 is a prime number
BaseRepresentation
bin1011111011010111000110…
…0111011100101000100101
31201102201122222000222200211
42332311301213130220211
53204331333434232442
643520405143135421
72522326036646512
oct276656147345045
951381588028624
1013114441320997
1141a6892262025
1215797bba44571
137418c03551c3
14334a56ddc309
1517b20b62b617
hexbed719dca25

13114441320997 has 2 divisors, whose sum is σ = 13114441320998. Its totient is φ = 13114441320996.

The previous prime is 13114441320991. The next prime is 13114441321031. The reversal of 13114441320997 is 79902314441131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7214429468961 + 5900011852036 = 2685969^2 + 2428994^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13114441320997 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13114441320997.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13114441320991) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557220660498 + 6557220660499.

It is an arithmetic number, because the mean of its divisors is an integer number (6557220660499).

Almost surely, 213114441320997 is an apocalyptic number.

It is an amenable number.

13114441320997 is a deficient number, since it is larger than the sum of its proper divisors (1).

13114441320997 is an equidigital number, since it uses as much as digits as its factorization.

13114441320997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 653184, while the sum is 49.

The spelling of 13114441320997 in words is "thirteen trillion, one hundred fourteen billion, four hundred forty-one million, three hundred twenty thousand, nine hundred ninety-seven".