Base | Representation |
---|---|
bin | 1011111011010111001000… |
… | …1000100011100101100001 |
3 | 1201102201200120100221100201 |
4 | 2332311302020203211201 |
5 | 3204331343200001400 |
6 | 43520410053145201 |
7 | 2522326203505420 |
oct | 276656210434541 |
9 | 51381616327321 |
10 | 13114450000225 |
11 | 41a689714a942 |
12 | 157980292b201 |
13 | 7418c20a3842 |
14 | 334a5821b2b7 |
15 | 17b20c29306a |
hex | bed72223961 |
13114450000225 has 12 divisors (see below), whose sum is σ = 18585049143424. Its totient is φ = 8992765714320.
The previous prime is 13114450000213. The next prime is 13114450000277. The reversal of 13114450000225 is 52200005441131.
13114450000225 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13114450000225 - 27 = 13114450000097 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13114450000193 and 13114450000202.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 37469856969 + ... + 37469857318.
Almost surely, 213114450000225 is an apocalyptic number.
It is an amenable number.
13114450000225 is a deficient number, since it is larger than the sum of its proper divisors (5470599143199).
13114450000225 is an equidigital number, since it uses as much as digits as its factorization.
13114450000225 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 74939714304 (or 74939714299 counting only the distinct ones).
The product of its (nonzero) digits is 4800, while the sum is 28.
Adding to 13114450000225 its reverse (52200005441131), we get a palindrome (65314455441356).
The spelling of 13114450000225 in words is "thirteen trillion, one hundred fourteen billion, four hundred fifty million, two hundred twenty-five", and thus it is an aban number.
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