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131145535 = 526229107
BaseRepresentation
bin1111101000100…
…01111100111111
3100010202212212001
413310101330333
5232033124120
621002523131
73151501333
oct764217477
9303685761
10131145535
1168034644
1237b064a7
132122a011
14135bb7c3
15b7a7e0a
hex7d11f3f

131145535 has 4 divisors (see below), whose sum is σ = 157374648. Its totient is φ = 104916424.

The previous prime is 131145533. The next prime is 131145551. The reversal of 131145535 is 535541131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 535541131 = 2323284397.

It is a cyclic number.

It is not a de Polignac number, because 131145535 - 21 = 131145533 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131145533) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13114549 + ... + 13114558.

It is an arithmetic number, because the mean of its divisors is an integer number (39343662).

Almost surely, 2131145535 is an apocalyptic number.

131145535 is a deficient number, since it is larger than the sum of its proper divisors (26229113).

131145535 is an equidigital number, since it uses as much as digits as its factorization.

131145535 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26229112.

The product of its digits is 4500, while the sum is 28.

The square root of 131145535 is about 11451.8791034485. The cubic root of 131145535 is about 508.0633136103.

Adding to 131145535 its reverse (535541131), we get a palindrome (666686666).

The spelling of 131145535 in words is "one hundred thirty-one million, one hundred forty-five thousand, five hundred thirty-five".

Divisors: 1 5 26229107 131145535