Base | Representation |
---|---|
bin | 1011111011011001011000… |
… | …1110000001010010110011 |
3 | 1201102210020202120001201222 |
4 | 2332312112032001102303 |
5 | 3204334113141144103 |
6 | 43520550121215255 |
7 | 2522350204435460 |
oct | 276662616012263 |
9 | 51383222501658 |
10 | 13115055412403 |
11 | 41a7077964a8a |
12 | 157995163152b |
13 | 74198a6459b9 |
14 | 334ab47b2667 |
15 | 17b2454ce638 |
hex | bed963814b3 |
13115055412403 has 16 divisors (see below), whose sum is σ = 15831358475520. Its totient is φ = 10613471894496.
The previous prime is 13115055412399. The next prime is 13115055412409. The reversal of 13115055412403 is 30421455051131.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 13115055412403 - 22 = 13115055412399 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13115055412409) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 168236525 + ... + 168314462.
It is an arithmetic number, because the mean of its divisors is an integer number (989459904720).
Almost surely, 213115055412403 is an apocalyptic number.
13115055412403 is a deficient number, since it is larger than the sum of its proper divisors (2716303063117).
13115055412403 is a wasteful number, since it uses less digits than its factorization.
13115055412403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 336551306.
The product of its (nonzero) digits is 36000, while the sum is 35.
The spelling of 13115055412403 in words is "thirteen trillion, one hundred fifteen billion, fifty-five million, four hundred twelve thousand, four hundred three".
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