13115255131535 has 4 divisors (see below), whose sum is σ = 15738306157848. Its totient is φ = 10492204105224.

The previous prime is 13115255131529. The next prime is 13115255131547. The reversal of 13115255131535 is 53513155251131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13115255131535 - 2¹⁰ = 13115255130511 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13115255131492 and 13115255131501.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1311525513149 + ... + 1311525513158.

It is an arithmetic number, because the mean of its divisors is an integer number (3934576539462).

Almost surely, 2^{13115255131535} is an apocalyptic number.

13115255131535 is a deficient number, since it is larger than the sum of its proper divisors (2623051026313).

13115255131535 is an equidigital number, since it uses as much as digits as its factorization.

13115255131535 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2623051026312.

The product of its digits is 168750, while the sum is 41.

The spelling of 13115255131535 in words is "thirteen trillion, one hundred fifteen billion, two hundred fifty-five million, one hundred thirty-one thousand, five hundred thirty-five".