Base | Representation |
---|---|
bin | 10011000101011101011… |
… | …110011111100100101111 |
3 | 11122101022000021210112222 |
4 | 103011131132133210233 |
5 | 132442010011100030 |
6 | 2442302102145555 |
7 | 163520006052641 |
oct | 23053536374457 |
9 | 4571260253488 |
10 | 1311533300015 |
11 | 4662443a11a4 |
12 | 192225a222bb |
13 | 968a5665c13 |
14 | 4769b1dc891 |
15 | 241b17093e5 |
hex | 1315d79f92f |
1311533300015 has 4 divisors (see below), whose sum is σ = 1573839960024. Its totient is φ = 1049226640008.
The previous prime is 1311533300009. The next prime is 1311533300023. The reversal of 1311533300015 is 5100033351131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1311533300015 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 131153329997 + ... + 131153330006.
It is an arithmetic number, because the mean of its divisors is an integer number (393459990006).
Almost surely, 21311533300015 is an apocalyptic number.
1311533300015 is a deficient number, since it is larger than the sum of its proper divisors (262306660009).
1311533300015 is an equidigital number, since it uses as much as digits as its factorization.
1311533300015 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 262306660008.
The product of its (nonzero) digits is 2025, while the sum is 26.
Adding to 1311533300015 its reverse (5100033351131), we get a palindrome (6411566651146).
The spelling of 1311533300015 in words is "one trillion, three hundred eleven billion, five hundred thirty-three million, three hundred thousand, fifteen".
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