1311604433161 has 4 divisors (see below), whose sum is σ = 1430841199824. Its totient is φ = 1192367666500.

The previous prime is 1311604433137. The next prime is 1311604433177. The reversal of 1311604433161 is 1613344061131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1311604433161 - 2²⁵ = 1311570878729 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1311604433561) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59618383315 + ... + 59618383336.

It is an arithmetic number, because the mean of its divisors is an integer number (357710299956).

Almost surely, 2^{1311604433161} is an apocalyptic number.

1311604433161 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1311604433161 is a deficient number, since it is larger than the sum of its proper divisors (119236766663).

1311604433161 is a wasteful number, since it uses less digits than its factorization.

1311604433161 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 119236766662.

The product of its (nonzero) digits is 15552, while the sum is 34.

Adding to 1311604433161 its reverse (1613344061131), we get a palindrome (2924948494292).

The spelling of 1311604433161 in words is "one trillion, three hundred eleven billion, six hundred four million, four hundred thirty-three thousand, one hundred sixty-one".