13116211441 has 4 divisors (see below), whose sum is σ = 13119077952. Its totient is φ = 13113344932.

The previous prime is 13116211397. The next prime is 13116211453. The reversal of 13116211441 is 14411261131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13116211441 - 2³³ = 4526276849 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13116211481) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1426381 + ... + 1435546.

It is an arithmetic number, because the mean of its divisors is an integer number (3279769488).

Almost surely, 2^13116211441 is an apocalyptic number.

It is an amenable number.

13116211441 is a deficient number, since it is larger than the sum of its proper divisors (2866511).

13116211441 is an equidigital number, since it uses as much as digits as its factorization.

13116211441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2866510.

The product of its digits is 576, while the sum is 25.

Adding to 13116211441 its reverse (14411261131), we get a palindrome (27527472572).

The spelling of 13116211441 in words is "thirteen billion, one hundred sixteen million, two hundred eleven thousand, four hundred forty-one".