Base | Representation |
---|---|
bin | 1011111011011110101000… |
… | …1111101010101001010001 |
3 | 1201102220220000012010211020 |
4 | 2332313222033222221101 |
5 | 3204400010033130230 |
6 | 43521342040310053 |
7 | 2522430143023503 |
oct | 276675217525121 |
9 | 51386800163736 |
10 | 13116465130065 |
11 | 41a7730690800 |
12 | 157a085772329 |
13 | 741b5371766b |
14 | 334ba9ad3d73 |
15 | 17b2c9143810 |
hex | bedea3eaa51 |
13116465130065 has 48 divisors (see below), whose sum is σ = 23068268221824. Its totient is φ = 6359323548160.
The previous prime is 13116465129947. The next prime is 13116465130081. The reversal of 13116465130065 is 56003156461131.
It is not a de Polignac number, because 13116465130065 - 211 = 13116465128017 is a prime.
It is a super-2 number, since 2×131164651300652 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13116465129999 and 13116465130026.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 87075604 + ... + 87226106.
It is an arithmetic number, because the mean of its divisors is an integer number (480588921288).
Almost surely, 213116465130065 is an apocalyptic number.
13116465130065 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13116465130065 is a deficient number, since it is larger than the sum of its proper divisors (9951803091759).
13116465130065 is a wasteful number, since it uses less digits than its factorization.
13116465130065 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 198550 (or 198539 counting only the distinct ones).
The product of its (nonzero) digits is 194400, while the sum is 42.
The spelling of 13116465130065 in words is "thirteen trillion, one hundred sixteen billion, four hundred sixty-five million, one hundred thirty thousand, sixty-five".
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