Base | Representation |
---|---|
bin | 11101110100101101111111… |
… | …011111001011110111101011 |
3 | 122012102100202011211000102112 |
4 | 131310231333133023313223 |
5 | 114143011231123242214 |
6 | 1142544521211152535 |
7 | 36425304231614450 |
oct | 3564557737136753 |
9 | 565370664730375 |
10 | 131166145134059 |
11 | 38880282485472 |
12 | 12864a6474574b |
13 | 5825bb6c70529 |
14 | 2456692307827 |
15 | 1026dec002a3e |
hex | 774b7f7cbdeb |
131166145134059 has 4 divisors (see below), whose sum is σ = 149904165867504. Its totient is φ = 112428124400616.
The previous prime is 131166145134043. The next prime is 131166145134097. The reversal of 131166145134059 is 950431541661131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131166145134059 - 24 = 131166145134043 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 131166145133998 and 131166145134016.
It is not an unprimeable number, because it can be changed into a prime (131166145134029) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9369010366712 + ... + 9369010366725.
It is an arithmetic number, because the mean of its divisors is an integer number (37476041466876).
Almost surely, 2131166145134059 is an apocalyptic number.
131166145134059 is a deficient number, since it is larger than the sum of its proper divisors (18738020733445).
131166145134059 is an equidigital number, since it uses as much as digits as its factorization.
131166145134059 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18738020733444.
The product of its (nonzero) digits is 1166400, while the sum is 50.
The spelling of 131166145134059 in words is "one hundred thirty-one trillion, one hundred sixty-six billion, one hundred forty-five million, one hundred thirty-four thousand, fifty-nine".
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