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131166145134097 is a prime number
BaseRepresentation
bin11101110100101101111111…
…011111001011111000010001
3122012102100202011211000110221
4131310231333133023320101
5114143011231123242342
61142544521211153041
736425304231614533
oct3564557737137021
9565370664730427
10131166145134097
11388802824854a7
1212864a64745781
135825bb6c70558
142456692307853
151026dec002a67
hex774b7f7cbe11

131166145134097 has 2 divisors, whose sum is σ = 131166145134098. Its totient is φ = 131166145134096.

The previous prime is 131166145134043. The next prime is 131166145134109. The reversal of 131166145134097 is 790431541661131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110695144422976 + 20471000711121 = 10521176^2 + 4524489^2 .

It is an emirp because it is prime and its reverse (790431541661131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131166145134097 - 211 = 131166145132049 is a prime.

It is a super-2 number, since 2×1311661451340972 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131166145134797) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65583072567048 + 65583072567049.

It is an arithmetic number, because the mean of its divisors is an integer number (65583072567049).

Almost surely, 2131166145134097 is an apocalyptic number.

It is an amenable number.

131166145134097 is a deficient number, since it is larger than the sum of its proper divisors (1).

131166145134097 is an equidigital number, since it uses as much as digits as its factorization.

131166145134097 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1632960, while the sum is 52.

The spelling of 131166145134097 in words is "one hundred thirty-one trillion, one hundred sixty-six billion, one hundred forty-five million, one hundred thirty-four thousand, ninety-seven".