Base | Representation |
---|---|
bin | 1011111011101010000111… |
… | …1100111111011111110011 |
3 | 1201110012211210201200020000 |
4 | 2332322201330333133303 |
5 | 3204422313043224413 |
6 | 43523011540521043 |
7 | 2522566416401133 |
oct | 276724174773763 |
9 | 51405753650200 |
10 | 13119547242483 |
11 | 41a8a72435450 |
12 | 157a7a59b0183 |
13 | 74222511b916 |
14 | 334dbd192ac3 |
15 | 17b409a07073 |
hex | beea1f3f7f3 |
13119547242483 has 80 divisors (see below), whose sum is σ = 21529658902752. Its totient is φ = 7895771136000.
The previous prime is 13119547242481. The next prime is 13119547242517. The reversal of 13119547242483 is 38424274591131.
13119547242483 is a `hidden beast` number, since 1 + 3 + 1 + 1 + 9 + 54 + 72 + 42 + 483 = 666.
It is not a de Polignac number, because 13119547242483 - 21 = 13119547242481 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13119547242481) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 75713503 + ... + 75886583.
Almost surely, 213119547242483 is an apocalyptic number.
13119547242483 is a deficient number, since it is larger than the sum of its proper divisors (8410111660269).
13119547242483 is a wasteful number, since it uses less digits than its factorization.
13119547242483 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 173698 (or 173689 counting only the distinct ones).
The product of its digits is 5806080, while the sum is 54.
The spelling of 13119547242483 in words is "thirteen trillion, one hundred nineteen billion, five hundred forty-seven million, two hundred forty-two thousand, four hundred eighty-three".
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