1312000100401 has 4 divisors (see below), whose sum is σ = 1347459562612. Its totient is φ = 1276540638192.

The previous prime is 1312000100399. The next prime is 1312000100413. The reversal of 1312000100401 is 1040010002131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 819792619776 + 492207480625 = 905424^2 + 701575^2 .

It is a cyclic number.

It is not a de Polignac number, because 1312000100401 - 2¹ = 1312000100399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1312000100461) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17729731050 + ... + 17729731123.

It is an arithmetic number, because the mean of its divisors is an integer number (336864890653).

Almost surely, 2^{1312000100401} is an apocalyptic number.

It is an amenable number.

1312000100401 is a deficient number, since it is larger than the sum of its proper divisors (35459462211).

1312000100401 is an equidigital number, since it uses as much as digits as its factorization.

1312000100401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 35459462210.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 1312000100401 its reverse (1040010002131), we get a palindrome (2352010102532).

The spelling of 1312000100401 in words is "one trillion, three hundred twelve billion, one hundred thousand, four hundred one".