Search a number
-
+
1312001314303 = 1936797934271
BaseRepresentation
bin10011000101111001010…
…111110100110111111111
311122102111121221101110111
4103011321113310313333
5132443434314024203
62442420341250451
7163534421111041
oct23057127646777
94572447841414
101312001314303
114664645a1269
12192336703a27
139694b5cc254
1447703429a91
15241dc85526d
hex131795f4dff

1312001314303 has 4 divisors (see below), whose sum is σ = 1318799248768. Its totient is φ = 1305203379840.

The previous prime is 1312001314259. The next prime is 1312001314313. The reversal of 1312001314303 is 3034131002131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1312001314303 - 213 = 1312001306111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1312001314313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3398966943 + ... + 3398967328.

It is an arithmetic number, because the mean of its divisors is an integer number (329699812192).

Almost surely, 21312001314303 is an apocalyptic number.

1312001314303 is a deficient number, since it is larger than the sum of its proper divisors (6797934465).

1312001314303 is an equidigital number, since it uses as much as digits as its factorization.

1312001314303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6797934464.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 1312001314303 its reverse (3034131002131), we get a palindrome (4346132316434).

The spelling of 1312001314303 in words is "one trillion, three hundred twelve billion, one million, three hundred fourteen thousand, three hundred three".

Divisors: 1 193 6797934271 1312001314303