Base | Representation |
---|---|
bin | 11101110101001101101001… |
… | …100010000111010110100011 |
3 | 122012112121111002122102121200 |
4 | 131311031221202013112203 |
5 | 114144040334423312403 |
6 | 1143012302145052243 |
7 | 36430616456042133 |
oct | 3565155142072643 |
9 | 565477432572550 |
10 | 131200136541603 |
11 | 38893735774018 |
12 | 1286b570327083 |
13 | 582917323902c |
14 | 24581988aaac3 |
15 | 1027c3b255ca3 |
hex | 7753698875a3 |
131200136541603 has 48 divisors (see below), whose sum is σ = 195268303994400. Its totient is φ = 84834868124160.
The previous prime is 131200136541563. The next prime is 131200136541619. The reversal of 131200136541603 is 306145631002131.
131200136541603 is a `hidden beast` number, since 1 + 3 + 1 + 2 + 0 + 0 + 1 + 3 + 6 + 5 + 41 + 603 = 666.
It is not a de Polignac number, because 131200136541603 - 28 = 131200136541347 is a prime.
It is not an unprimeable number, because it can be changed into a prime (131200136541673) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 258468213 + ... + 258975321.
It is an arithmetic number, because the mean of its divisors is an integer number (4068089666550).
Almost surely, 2131200136541603 is an apocalyptic number.
131200136541603 is a deficient number, since it is larger than the sum of its proper divisors (64068167452797).
131200136541603 is a wasteful number, since it uses less digits than its factorization.
131200136541603 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 511252 (or 511249 counting only the distinct ones).
The product of its (nonzero) digits is 38880, while the sum is 36.
Adding to 131200136541603 its reverse (306145631002131), we get a palindrome (437345767543734).
The spelling of 131200136541603 in words is "one hundred thirty-one trillion, two hundred billion, one hundred thirty-six million, five hundred forty-one thousand, six hundred three".
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