Base | Representation |
---|---|
bin | 11000011100000001… |
… | …11100010110011111 |
3 | 1020212100122120211011 |
4 | 30032000330112133 |
5 | 203332211430421 |
6 | 10005515440051 |
7 | 643061262436 |
oct | 141600742637 |
9 | 36770576734 |
10 | 13120030111 |
11 | 5622a078a1 |
12 | 2661a56027 |
13 | 1311209536 |
14 | 8c669211d |
15 | 51bc614e1 |
hex | 30e03c59f |
13120030111 has 4 divisors (see below), whose sum is σ = 13138535800. Its totient is φ = 13101524424.
The previous prime is 13120030073. The next prime is 13120030123. The reversal of 13120030111 is 11103002131.
13120030111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11103002131 = 13 ⋅854077087.
It is a cyclic number.
It is not a de Polignac number, because 13120030111 - 219 = 13119505823 is a prime.
It is a super-2 number, since 2×131200301112 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13120030091 and 13120030100.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13120030181) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9251781 + ... + 9253198.
It is an arithmetic number, because the mean of its divisors is an integer number (3284633950).
Almost surely, 213120030111 is an apocalyptic number.
13120030111 is a deficient number, since it is larger than the sum of its proper divisors (18505689).
13120030111 is an equidigital number, since it uses as much as digits as its factorization.
13120030111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18505688.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 13120030111 its reverse (11103002131), we get a palindrome (24223032242).
The spelling of 13120030111 in words is "thirteen billion, one hundred twenty million, thirty thousand, one hundred eleven".
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