Base | Representation |
---|---|
bin | 10011000101111001100… |
… | …010001100111100100111 |
3 | 11122102111211001120122201 |
4 | 103011321202030330213 |
5 | 132443441013044333 |
6 | 2442420515435331 |
7 | 163534453200142 |
oct | 23057142147447 |
9 | 4572454046581 |
10 | 1312004034343 |
11 | 466466089932 |
12 | 1923375b5b47 |
13 | 9694c042342 |
14 | 47703937059 |
15 | 241dcbe117d |
hex | 1317988cf27 |
1312004034343 has 4 divisors (see below), whose sum is σ = 1316673088128. Its totient is φ = 1307334980560.
The previous prime is 1312004034337. The next prime is 1312004034427. The reversal of 1312004034343 is 3434304002131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1312004034343 - 217 = 1312003903271 is a prime.
It is a super-2 number, since 2×13120040343432 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1312004004343) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2334526471 + ... + 2334527032.
It is an arithmetic number, because the mean of its divisors is an integer number (329168272032).
Almost surely, 21312004034343 is an apocalyptic number.
1312004034343 is a deficient number, since it is larger than the sum of its proper divisors (4669053785).
1312004034343 is an equidigital number, since it uses as much as digits as its factorization.
1312004034343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4669053784.
The product of its (nonzero) digits is 10368, while the sum is 28.
Adding to 1312004034343 its reverse (3434304002131), we get a palindrome (4746308036474).
The spelling of 1312004034343 in words is "one trillion, three hundred twelve billion, four million, thirty-four thousand, three hundred forty-three".
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