13120110110041 has 4 divisors (see below), whose sum is σ = 14312847392784. Its totient is φ = 11927372827300.

The previous prime is 13120110109987. The next prime is 13120110110071. The reversal of 13120110110041 is 14001101102131.

13120110110041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13120110110041 - 2¹⁹ = 13120109585753 is a prime.

It is a super-2 number, since 2×13120110110041² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13120110109997 and 13120110110024.

It is not an unprimeable number, because it can be changed into a prime (13120110110071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 596368641355 + ... + 596368641376.

It is an arithmetic number, because the mean of its divisors is an integer number (3578211848196).

Almost surely, 2^{13120110110041} is an apocalyptic number.

13120110110041 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13120110110041 is a deficient number, since it is larger than the sum of its proper divisors (1192737282743).

13120110110041 is a wasteful number, since it uses less digits than its factorization.

13120110110041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1192737282742.

The product of its (nonzero) digits is 24, while the sum is 16.

Adding to 13120110110041 its reverse (14001101102131), we get a palindrome (27121211212172).

The spelling of 13120110110041 in words is "thirteen trillion, one hundred twenty billion, one hundred ten million, one hundred ten thousand, forty-one".