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131201131220323 = 909833144203531
BaseRepresentation
bin11101110101001110100100…
…110100100000110101100011
3122012112201001102022100022021
4131311032210310200311203
5114144044404043022243
61143012545000322311
736430653224501113
oct3565164464406543
9565481042270267
10131201131220323
11388940a619294a
121286b7a9473397
1358292a1332118
142458250a31043
151027c987356ed
hex7753a4d20d63

131201131220323 has 4 divisors (see below), whose sum is σ = 131201276333688. Its totient is φ = 131200986106960.

The previous prime is 131201131220273. The next prime is 131201131220359. The reversal of 131201131220323 is 323022131102131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131201131220323 - 233 = 131192541285731 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131201131220623) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 71191933 + ... + 73011598.

It is an arithmetic number, because the mean of its divisors is an integer number (32800319083422).

Almost surely, 2131201131220323 is an apocalyptic number.

131201131220323 is a deficient number, since it is larger than the sum of its proper divisors (145113365).

131201131220323 is an equidigital number, since it uses as much as digits as its factorization.

131201131220323 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 145113364.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 131201131220323 its reverse (323022131102131), we get a palindrome (454223262322454).

The spelling of 131201131220323 in words is "one hundred thirty-one trillion, two hundred one billion, one hundred thirty-one million, two hundred twenty thousand, three hundred twenty-three".

Divisors: 1 909833 144203531 131201131220323