131201203241041 has 4 divisors (see below), whose sum is σ = 132006118598512. Its totient is φ = 130396287883572.

The previous prime is 131201203241027. The next prime is 131201203241047. The reversal of 131201203241041 is 140142302102131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131201203241041 - 2¹¹ = 131201203238993 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131201203240997 and 131201203241015.

It is not an unprimeable number, because it can be changed into a prime (131201203241047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 402457678491 + ... + 402457678816.

It is an arithmetic number, because the mean of its divisors is an integer number (33001529649628).

Almost surely, 2^{131201203241041} is an apocalyptic number.

It is an amenable number.

131201203241041 is a deficient number, since it is larger than the sum of its proper divisors (804915357471).

131201203241041 is an equidigital number, since it uses as much as digits as its factorization.

131201203241041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 804915357470.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 131201203241041 its reverse (140142302102131), we get a palindrome (271343505343172).

The spelling of 131201203241041 in words is "one hundred thirty-one trillion, two hundred one billion, two hundred three million, two hundred forty-one thousand, forty-one".