Base | Representation |
---|---|
bin | 1011111011101100010010… |
… | …1101010011101100000000 |
3 | 1201110021100102220202122101 |
4 | 2332323010231103230000 |
5 | 3204430011331132230 |
6 | 43523145450320144 |
7 | 2522620026523564 |
oct | 276730455235400 |
9 | 51407312822571 |
10 | 13120130333440 |
11 | 41a92415942a9 |
12 | 157a929129054 |
13 | 7422b8b76c60 |
14 | 3350367b76a4 |
15 | 17b440cd4aca |
hex | beec4b53b00 |
13120130333440 has 1152 divisors, whose sum is σ = 38445179351040. Its totient is φ = 4246074556416.
The previous prime is 13120130333389. The next prime is 13120130333459. The reversal of 13120130333440 is 4433303102131.
13120130333440 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 13120130333399 and 13120130333408.
It is an unprimeable number.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 17658317709 + ... + 17658318451.
It is an arithmetic number, because the mean of its divisors is an integer number (33372551520).
Almost surely, 213120130333440 is an apocalyptic number.
13120130333440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13120130333440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19222589675520).
13120130333440 is an abundant number, since it is smaller than the sum of its proper divisors (25325049017600).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13120130333440 is a wasteful number, since it uses less digits than its factorization.
13120130333440 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 909 (or 895 counting only the distinct ones).
The product of its (nonzero) digits is 7776, while the sum is 28.
Adding to 13120130333440 its reverse (4433303102131), we get a palindrome (17553433435571).
The spelling of 13120130333440 in words is "thirteen trillion, one hundred twenty billion, one hundred thirty million, three hundred thirty-three thousand, four hundred forty".
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