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131201421010042 = 265600710505021
BaseRepresentation
bin11101110101001110110110…
…000101111110010001111010
3122012112201210121121012001211
4131311032312011332101322
5114144101002234310132
61143013033431433334
736430663343614105
oct3565166605762172
9565481717535054
10131201421010042
1138894234823189
121286b86a52584a
135829319396726
14245827b30773c
151027cb3dc9147
hex7753b617e47a

131201421010042 has 4 divisors (see below), whose sum is σ = 196802131515066. Its totient is φ = 65600710505020.

The previous prime is 131201421010031. The next prime is 131201421010057. The reversal of 131201421010042 is 240010124102131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 84023603940721 + 47177817069321 = 9166439^2 + 6868611^2 .

It is a junction number, because it is equal to n+sod(n) for n = 131201421009995 and 131201421010022.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32800355252509 + ... + 32800355252512.

Almost surely, 2131201421010042 is an apocalyptic number.

131201421010042 is a deficient number, since it is larger than the sum of its proper divisors (65600710505024).

131201421010042 is an equidigital number, since it uses as much as digits as its factorization.

131201421010042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65600710505023.

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 131201421010042 its reverse (240010124102131), we get a palindrome (371211545112173).

The spelling of 131201421010042 in words is "one hundred thirty-one trillion, two hundred one billion, four hundred twenty-one million, ten thousand, forty-two".

Divisors: 1 2 65600710505021 131201421010042