Base | Representation |
---|---|
bin | 11101110101001110110110… |
… | …000101111110010001111010 |
3 | 122012112201210121121012001211 |
4 | 131311032312011332101322 |
5 | 114144101002234310132 |
6 | 1143013033431433334 |
7 | 36430663343614105 |
oct | 3565166605762172 |
9 | 565481717535054 |
10 | 131201421010042 |
11 | 38894234823189 |
12 | 1286b86a52584a |
13 | 5829319396726 |
14 | 245827b30773c |
15 | 1027cb3dc9147 |
hex | 7753b617e47a |
131201421010042 has 4 divisors (see below), whose sum is σ = 196802131515066. Its totient is φ = 65600710505020.
The previous prime is 131201421010031. The next prime is 131201421010057. The reversal of 131201421010042 is 240010124102131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 84023603940721 + 47177817069321 = 9166439^2 + 6868611^2 .
It is a junction number, because it is equal to n+sod(n) for n = 131201421009995 and 131201421010022.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32800355252509 + ... + 32800355252512.
Almost surely, 2131201421010042 is an apocalyptic number.
131201421010042 is a deficient number, since it is larger than the sum of its proper divisors (65600710505024).
131201421010042 is an equidigital number, since it uses as much as digits as its factorization.
131201421010042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65600710505023.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 131201421010042 its reverse (240010124102131), we get a palindrome (371211545112173).
The spelling of 131201421010042 in words is "one hundred thirty-one trillion, two hundred one billion, four hundred twenty-one million, ten thousand, forty-two".
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