13120143241333 has 4 divisors (see below), whose sum is σ = 13810677096160. Its totient is φ = 12429609386508.

The previous prime is 13120143241277. The next prime is 13120143241363. The reversal of 13120143241333 is 33314234102131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13120143241333 - 2²⁹ = 13119606370421 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13120143241295 and 13120143241304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13120143241363) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 345266927385 + ... + 345266927422.

It is an arithmetic number, because the mean of its divisors is an integer number (3452669274040).

Almost surely, 2^{13120143241333} is an apocalyptic number.

It is an amenable number.

13120143241333 is a deficient number, since it is larger than the sum of its proper divisors (690533854827).

13120143241333 is an equidigital number, since it uses as much as digits as its factorization.

13120143241333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 690533854826.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 13120143241333 its reverse (33314234102131), we get a palindrome (46434377343464).

The spelling of 13120143241333 in words is "thirteen trillion, one hundred twenty billion, one hundred forty-three million, two hundred forty-one thousand, three hundred thirty-three".