Base | Representation |
---|---|
bin | 11101110101010000010110… |
… | …001011100111101100011011 |
3 | 122012112212221222001000001021 |
4 | 131311100112023213230123 |
5 | 114144112302433300011 |
6 | 1143013501420303311 |
7 | 36431051320312003 |
oct | 3565202613475433 |
9 | 565485858030037 |
10 | 131203033103131 |
11 | 38894991804620 |
12 | 1287003a3a1b37 |
13 | 5829515374972 |
14 | 2458391469003 |
15 | 1027d5a6b6471 |
hex | 7754162e7b1b |
131203033103131 has 4 divisors (see below), whose sum is σ = 143130581567064. Its totient is φ = 119275484639200.
The previous prime is 131203033103123. The next prime is 131203033103167. The reversal of 131203033103131 is 131301330302131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131203033103131 - 23 = 131203033103123 is a prime.
It is a super-2 number, since 2×1312030331031312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 131203033103096 and 131203033103105.
It is not an unprimeable number, because it can be changed into a prime (131203033803131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5963774231950 + ... + 5963774231971.
It is an arithmetic number, because the mean of its divisors is an integer number (35782645391766).
Almost surely, 2131203033103131 is an apocalyptic number.
131203033103131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
131203033103131 is a deficient number, since it is larger than the sum of its proper divisors (11927548463933).
131203033103131 is a wasteful number, since it uses less digits than its factorization.
131203033103131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11927548463932.
The product of its (nonzero) digits is 1458, while the sum is 25.
Adding to 131203033103131 its reverse (131301330302131), we get a palindrome (262504363405262).
The spelling of 131203033103131 in words is "one hundred thirty-one trillion, two hundred three billion, thirty-three million, one hundred three thousand, one hundred thirty-one".
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